﻿<?xml version="1.0" encoding="utf-8"?><rss version="2.0"><channel><copyright>Copyright 2003-2026 Bug &amp; dizzy.hr</copyright><ttl>30</ttl><pubDate>Thu, 07 May 2026 23:45:40 GMT</pubDate><managingEditor>pisma@bug.hr</managingEditor><language>hr</language><lastBuildDate>Thu, 10 Nov 2011 17:49:35 GMT</lastBuildDate><description>Tema unutar podforuma Programiranje</description><title>C++ - učitava broj n(n&gt;1), računa Xi(X0, X1..Xn)</title><link>http://bugforum.azurewebsites.net/forum/topic/programiranje/c-ucitava-broj-nn1-racuna-xix0-x1xn/124469.aspx</link><image><url>http://www.bug.hr/images/forum-rss.gif</url></image><item><title>Re: Pomoc sa programom u c++</title><description>hvala na ispravku...rijesio sam to..:)</description><link>http://bugforum.azurewebsites.net/forum/post/programiranje/c-ucitava-broj-nn1-racuna-xix0-x1xn/2422922.aspx</link><pubDate>Thu, 10 Nov 2011 17:49:35 GMT</pubDate><guid isPermaLink="false">86f3bb8c4987ced7cd94bc27baf22a6e</guid><category /></item><item><title>Pomoc sa programom u c++</title><description>Lose si ispisao zadatak ako mene pitas, valjda mislis na xi = 2 * xi-1 +3 + xi-2 , tako da:&amp;nbsp;X2=2*X1 +3 + X0&amp;nbsp;&amp;nbsp;= 7X3=2*X2 + 3 + X1&amp;nbsp;&amp;nbsp;= 19X4 =2 * X3 + ...&amp;nbsp;Ništa napeto.</description><link>http://bugforum.azurewebsites.net/forum/post/programiranje/c-ucitava-broj-nn1-racuna-xix0-x1xn/2421163.aspx</link><pubDate>Wed, 09 Nov 2011 23:08:43 GMT</pubDate><guid isPermaLink="false">3348b16212f56baea2bcaea4a2a18acc</guid><category /></item><item><title>Pomoc sa programom u c++</title><description>Napisati program koji učitava broj n(n&amp;gt;1) i zatim računa Xi(X0,X1,X2,...Xn-1,Xn) zadan po formuli Xi=2*Xi-1+3+Xi-2.Početne vrijednosti su X0=1 i X1=2.U svakom koraku ispisivati Xi.&amp;nbsp;Dobio sam p...</description><link>http://bugforum.azurewebsites.net/forum/post/programiranje/c-ucitava-broj-nn1-racuna-xix0-x1xn/2420944.aspx</link><pubDate>Wed, 09 Nov 2011 21:42:00 GMT</pubDate><guid isPermaLink="false">ad332c438243e14e5afa8a27e4415587</guid><category /></item></channel></rss>